循环结构实例002

2019年5月4日吴代鹏 C

输入n个整数，求这n个数中的偶数平均值，并输出。

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#include <stdio.h>
int main()
{
    int n, i, x, sum=0, count=0;
    float ave=0;
    printf("Please enter how many integer you want enter: \n");
    scanf("%d", &n);
    for (i=1; i<=n; i++)
    {
        printf("Please enter your No.%d integer.\n", i);
        scanf("%d", &x);
        printf("Your No.%d integer is: %d\n", i, x);
        if(x%2 == 0)
        {
            count++;
            sum += x;
        }
    }
    ave = (double)sum/count;
    printf("The average of every even integer you have enter is: %.2f\n", ave);
    return 0;
}